Taking Maths Further Podcast Peter Rowlett and Katie Steckles

This week the topic was calculus and differentiation. We talked to Florencia Tettamanti, who’s a mathematician working on fluid dynamics. We talked about how Flo uses calculus to study the motion of fluids like air and water, and what it’s like to be a research mathematician. Interesting links: Basic differentiation, at s-cool Differential equations, at the University of Surrey website Fluid dynamics on Wikipedia NSF videos on Fluid Mechanics - YouTube playlist Puzzle: If your function is given by y = x2 - 6x + 13, what is the minimum value of y, and for which value of x does the function give this value? Solution: If you plot the points x=1, x=2, x=3 and x=4 you can clearly see the curve of this graph and that it seems to have a maximum at x=3, for which the value of y is 4. To see what the graph looks like, you can input the equation into Wolfram Alpha. Another way to see this is to rearrange the equation: x2-6x+13 = (x-3)2+4, and by examining this equation we can see that this is just an x graph, shifted across by 3 and up by 4, so its turning point and hence the minimum will be at x=3 and y=4. If you know how to use calculus, you can find the turning point more easily - if you differentiate x2-6x+13 you get 2x - 6, which will equal zero when x=3, and putting this value back into the original equation gives y=4. Show/Hide

This week the topic was mechanics and friction. We interviewed Dan Hett, who works for CBBC writing computer games for their website. We talked about his work and how he uses a lot of mathematics in modelling how characters move, and making sure that’s done in a realistic way. Interesting links: CBBC games website CBeebies story app (with pop-up book!) Game physics on Wikipedia A-level Mechanics topics at MathsRevision.net Friction and Coefficients of Friction at Engineering Toolbox (with some example values) Coefficient of friction on Wikipedia Puzzle: Susan the Hedgehog runs at 20cm/s across the screen while the run button is held down. Once the run button is released, she slows down with constant deceleration of 8.5cm/s2. Will she stop within 32cm more of screen? Solution: The time taken to stop can be calculated by knowing that every second travelled, 8.5cm/s of speed is lost, so after 20/8.5=2.35 seconds, speed will be zero. We can approximate this deceleration by imagining Susan is travelling at 20cm/s for 1 second, 11.5cm/s for 1 second and 3cm/s for the remaining 0.35 seconds until she stops. This will cover more distance than the actual motion does (as your speed is lower than this for most of the time), but will cause you to travel only 31.6cm - so you will definitely stop within 32cm. (In actual fact, the distance taken to stop will be 23.53cm, because your speed continues to decrease at a constant rate for the whole time. In order to work this out, you need to use a little calculus!) Show/Hide

This week the topic was Fourier analysis. We interviewed Heather Williams, who’s a medical physicist and works with Positron Emission Tomography (PET) scanners, as well as other medical scanning devices. We talked about her work and how maths is important in converting data from the scanner into images that can be used to diagnose patients. Interesting links: PET scanners on the NHS website Being a Medical Physicist on the NHS careers website Central Manchester University Hospitals, Heather's employer Shape of the sine and cosine graphs at BBC Bitesize An interactive guide to the Fourier transform at BetterExplained.com XKCD comic 'Fourier' Puzzle: If a function is made by adding sin(x) + cos(x), what’s the maximum value attained by this function? Solution: This is a periodic function, which repeats every 180 degrees (or π radians). Its maximum value is the square root of two, or √2 = 1.414213..., which it first reaches at a value of 45 degrees, or π/4. The function varies between √2 and -√2, and it looks like a sin curve. The function can also be written as √ 2 + sin(θ + π/4). For a graph of the function, and more detail, input it into Wolfram Alpha. Show/Hide

This week the topic was mathematical modelling and linear programming. We interviewed Rick Crawford from AMEC, who’s a mathematician studying decommissioning of nuclear reactors, and using mathematical models to determine whether it’s safe to continue using a particular reactor given that it may have degraded over time, but without actually building a physical model of it. Interesting links: Nuclear Power Plant at HowStuffWorks Mathematical model on Wikipedia Small angle approximation at John Cook's blog The Endeavour Linear programming at Purple Math Puzzle: A rod sits inside a cylindrical tube of the same height. The tube is 193mm tall, and 50mm in diameter. We assume the rod has zero thickness. What’s the maximum angle away from vertical that the rod can make (to the nearest degree)? Solution: You can imagine the rod as being a line inside a rectangle, since the cylinder is the same all the way round. Then, you need to calculate the angle made by the rod when it’s touching one bottom corner of the rectangle and resting against the opposite side. This will be a triangle whose base is 50mm and hypotenuse is the length of the rod. The angle from the vertical will be the top corner, and the sin of this angle will be the opposite (base of the triangle) over the hypotenuse. So the angle will be sin(50mm/193mm), which is 15 degrees to the nearest degree. Show/Hide

This week the topic was statistical distributions and actuarial science. We interviewed Richard Harland, who works in risk management for an insurance firm. We talked to him about his work as an actuary, and how he uses statistical distributions like the normal distribution to predict the probability of risky events. Interesting links: Normal distribution on Wikipedia Normal distributions at Maths Is Fun Introduction to being an actuary at the Actuarial Institute website Be an actuary website Puzzle: Your factory packages crisps into bags using a machine which isn’t completely accurate and the weight of crisps which ends up in each bag varies according to a normal distribution. The mean weight of a bag is 154g, and the standard deviation is 8g. The bags are labelled as containing 150g of crisps, but 31% of bags produced by the machine are underweight. To what value should you change your mean weight to make sure 95% of bags weigh more than 150g? Solution: On a normal distribution curve, 95% of values will fall within two standard deviations of the mean. This means in order to ensure 95% of crisp packets weigh 150g or more, we need 150g to be two standard deviations away from the mean - so the mean needs to be 150g + (2 x 8g) = 166g. Show/Hide

This week the topic was mathematics and money, and how maths is used in finance. We interviewed Sarah O’Rourke, who’s an accountant working on the problem of moving cash around to where it’s needed in cash machines. We discussed the ways she uses mathematical modelling to predict where demand for cash will be high, and also the other types of work that accountants do, and the different ways to become an accountant. Interesting links: Accounting on Wikipedia Double entry bookkeeping at Dummies.com What is Financial Mathematics? at Plus Magazine Maths games - percentages at IXL Tax Matters at HMRC Money Talks, interactive game at the NI Curriculum website Puzzle: Using only £20 and £50 notes, what’s the largest multiple of £10 you can’t make? In an imaginary scenario where the only notes are £30 and £70, again what’s the largest multiple of £10 you can’t make? Why do you think we use the denominations of currency that we do use? Solution: Using only £20 and £50 notes, it’s not possible to make £10 or £30, but all other multiples of £10 are possible. This can be proven by noting that £20 x 2 = £40, and £50 x 1 = £50, and from here every other multiple of £10 can be made by adding different numbers of £20 to either of these base amounts. If our notes are £30 and £70, we can’t make £50, £80 or £110, but all other multiples of £10 above £110 are possible. This can be proven by noticing that once you can make three consecutive multiples of £10, any other can be obtained by adding £30 notes - and in this case, we can make £120 = 4 x £30, £130 = £70 + 2 x £30, and £140 = 2 x £70 so we can then get £150, £160 and £170 by adding £30 to each, and so on. The notes currently in use (£5, £10, £20 and (rarely) £50) have been chosen so that it’s possible to make any amount that’s a multiple of £5 using relatively few notes. We don’t need a £30, as it can be made easily using £10 + £20. The system is designed to make it as easy as possible to make any amount, while keeping the number of different types of note needed relatively small. Show/Hide