The 1948 World Series matched the Cleveland Indians against the Boston Braves. The Braves had won the National League pennant for the first time since the "Miracle Braves" team of 1914. The Indians spoiled a chance for the only all-Boston World Series by winning a one-game playoff against the Boston Red Sox.[1] Though superstar pitcher Bob Feller failed to win either of his two starts, the Indians won the Series in six games to capture their second championship and their first since 1920 (as well as their last to the present date).It was the first World Series to be televised on a nationwide network and was announced by famed sportcasters Red Barber, Tom Hussey (in Boston) and Van Patrick (in Cleveland).[2]This was the only World Series from 1947 to 1958 not to feature a New York team, and also the last World Series until 1957 not won by a New York team (which the Braves won, except they had relocated to Milwaukee by then). Both teams would meet again in the 1995 World Series—by that time, the Braves had moved to Atlanta. Game 5 Sunday, October 10, 1948 at Cleveland Stadium in Cleveland, Ohio Team123456789RHE Boston 3 0 1 0 0 1 6 0 0 11 12 0 Cleveland 1 0 0 4 0 0 0 0 0 5 6 2 WP: Warren Spahn (1–1)   LP: Bob Feller (0–2) Home runs: BOS: Bob Elliott 2 (2), Bill Salkeld (1) CLE: Dale Mitchell (1), Jim Hegan (1) Satchel Paige appeared for the Indians, becoming the first black pitcher to take the mound in World Series history. The previous day's single-game attendance record was broken with 86,288 fans.